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  • Hydrochloric Acid Dilution: Step-by-Step Calculation & Solution
    Here's how to solve this dilution problem:

    Understanding the Concepts

    * Molarity (M): Represents the concentration of a solution, expressed as moles of solute per liter of solution.

    * Dilution: The process of reducing the concentration of a solution by adding more solvent (usually water).

    * The Dilution Equation: M₁V₁ = M₂V₂

    * M₁ = Initial molarity of the concentrated solution

    * V₁ = Initial volume of the concentrated solution

    * M₂ = Final molarity of the diluted solution

    * V₂ = Final volume of the diluted solution

    Solving the Problem

    1. Identify the knowns:

    * M₁ = 1.75 M (initial molarity of HCl)

    * M₂ = 0.250 M (final molarity of HCl)

    * V₂ = 0.500 L (final volume of the diluted solution)

    2. Identify the unknown:

    * V₁ = ? (initial volume of the concentrated HCl solution)

    3. Apply the dilution equation:

    * M₁V₁ = M₂V₂

    * (1.75 M) * V₁ = (0.250 M) * (0.500 L)

    4. Solve for V₁:

    * V₁ = (0.250 M * 0.500 L) / 1.75 M

    * V₁ = 0.0714 L

    Answer: You would need to dilute 0.0714 L (or 71.4 mL) of 1.75 M hydrochloric acid with water to prepare 0.500 L of 0.250 M hydrochloric acid.

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