When ethanoic acid (CH₃COOH) reacts with calcium oxide (CaO), the salt formed is calcium ethanoate (Ca(CH₃COO)₂).

Here's the balanced chemical equation for the reaction:

2CH₃COOH + CaO → Ca(CH₃COO)₂ + H₂O

Explanation:

* Ethanoic acid is a weak acid.

* Calcium oxide is a basic oxide.

* When an acid reacts with a basic oxide, a salt and water are formed.

* In this case, the calcium ions (Ca²⁺) from calcium oxide combine with the ethanoate ions (CH₃COO⁻) from ethanoic acid to form calcium ethanoate.

Therefore, the salt formed is calcium ethanoate.