You're close, but the products of the reaction are CaS (calcium sulfide) and NaCl (sodium chloride). Here's how to write the ionic equation:

1. Write the balanced chemical equation:

CaCl₂(aq) + Na₂S(aq) → CaS(s) + 2 NaCl(aq)

2. Break down the soluble ionic compounds into their ions:

* CaCl₂(aq) → Ca²⁺(aq) + 2 Cl⁻(aq)

* Na₂S(aq) → 2 Na⁺(aq) + S²⁻(aq)

* 2 NaCl(aq) → 2 Na⁺(aq) + 2 Cl⁻(aq)

3. Write the complete ionic equation:

Ca²⁺(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + S²⁻(aq) → CaS(s) + 2 Na⁺(aq) + 2 Cl⁻(aq)

4. Cancel out spectator ions (ions that appear on both sides of the equation):

The spectator ions are Na⁺ and Cl⁻.

5. Write the net ionic equation:

Ca²⁺(aq) + S²⁻(aq) → CaS(s)

This is the ionic equation for the reaction of calcium chloride and sodium sulfide.