1. Write the balanced chemical equation:

H₂SO₄(aq) + 2LiOH(aq) → Li₂SO₄(aq) + 2H₂O(l)

2. Calculate moles of LiOH:

* Molar mass of LiOH = 6.941 g/mol + 15.999 g/mol + 1.008 g/mol = 23.948 g/mol

* Moles of LiOH = (7.2280 g) / (23.948 g/mol) = 0.3018 mol

3. Determine the mole ratio from the balanced equation:

* The equation shows that 1 mole of H₂SO₄ reacts with 2 moles of LiOH.

4. Calculate moles of H₂SO₄ needed:

* Moles of H₂SO₄ = (0.3018 mol LiOH) / (2 mol LiOH/mol H₂SO₄) = 0.1509 mol H₂SO₄

5. Calculate the volume of H₂SO₄ solution:

* Volume = Moles / Molarity

* Volume = (0.1509 mol) / (4.494 M) = 0.0336 L

Therefore, you would need 0.0336 liters (or 33.6 mL) of the 4.494 M H₂SO₄ solution to reach the equivalence point with 7.2280 g of LiOH.