Calculating Moles of Ammonium Ions in Carbonate Compounds

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Here's how to solve this problem:

1. Identify the compound:

You're asking about the number of ammonium ions (NH₄⁺) in a sample of carbonate. Since carbonates contain the CO₃²⁻ ion, we need to consider what ammonium compound is involved. Let's assume you are referring to ammonium carbonate ((NH₄)₂CO₃), which is a common compound.

2. Determine the molar mass of ammonium carbonate:

* Molar mass of (NH₄)₂CO₃ = (2 * 14.01 g/mol (N)) + (8 * 1.01 g/mol (H)) + (12.01 g/mol (C)) + (3 * 16.00 g/mol (O))

* Molar mass of (NH₄)₂CO₃ = 96.09 g/mol

3. Calculate the moles of ammonium carbonate:

* Moles of (NH₄)₂CO₃ = mass / molar mass

* Moles of (NH₄)₂CO₃ = 8.718 g / 96.09 g/mol

* Moles of (NH₄)₂CO₃ ≈ 0.0907 mol

4. Determine the mole ratio of ammonium ions to ammonium carbonate:

* In one formula unit of (NH₄)₂CO₃, there are two ammonium ions (NH₄⁺).

* Therefore, the mole ratio is 2:1.

5. Calculate the moles of ammonium ions:

* Moles of NH₄⁺ = (moles of (NH₄)₂CO₃) * (2 moles NH₄⁺ / 1 mole (NH₄)₂CO₃)