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  • Lewis Structure & Nonbonding Electrons for CH2Br2 (Dibromomethane)
    Here's how to draw the Lewis structure for CH2Br2 (dibromomethane) and determine the number of nonbonding electrons:

    1. Determine the total number of valence electrons:

    * Carbon (C) has 4 valence electrons.

    * Hydrogen (H) has 1 valence electron each (2 total).

    * Bromine (Br) has 7 valence electrons each (14 total).

    Total valence electrons = 4 + 2 + 14 = 20

    2. Determine the central atom:

    * Carbon is the least electronegative atom, so it will be the central atom.

    3. Draw a single bond between the central atom and the surrounding atoms:

    * Connect the carbon atom to the two hydrogen atoms and the two bromine atoms with single bonds.

    4. Complete the octets of the surrounding atoms:

    * Each hydrogen atom needs 2 electrons to complete its duet.

    * Each bromine atom needs 8 electrons to complete its octet.

    5. Complete the octet of the central atom (if necessary):

    * Carbon has 4 electrons from the single bonds. It needs 4 more electrons to complete its octet.

    6. Add lone pairs to the surrounding atoms:

    * Each bromine atom has 3 lone pairs (6 electrons) to complete its octet.

    Lewis Structure:

    ```

    H

    |

    H - C - Br

    |

    Br

    ```

    Nonbonding Electrons:

    * Each bromine atom has 6 nonbonding electrons (3 lone pairs).

    * There are two bromine atoms, so there are a total of 12 nonbonding electrons.

    Therefore, there are 12 nonbonding electrons in CH2Br2.

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