1. Write the balanced molecular equation:
Cu(NO₃)₂ (aq) + BaCl₂ (aq) → CuCl₂ (aq) + Ba(NO₃)₂ (aq)
2. Write the complete ionic equation:
Cu²⁺ (aq) + 2NO₃⁻ (aq) + Ba²⁺ (aq) + 2Cl⁻ (aq) → Cu²⁺ (aq) + 2Cl⁻ (aq) + Ba²⁺ (aq) + 2NO₃⁻ (aq)
3. Identify the spectator ions:
Spectator ions are those that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Cu²⁺, NO₃⁻, Ba²⁺, and Cl⁻.
4. Cancel out the spectator ions to get the net ionic equation:
Since all ions are spectator ions, the net ionic equation is null or no reaction.
Conclusion:
The reaction of copper(II) nitrate and barium chloride does not produce a precipitate or any other observable change. Therefore, the net ionic equation is null, indicating that no reaction occurs.
