Zn(s) + 2NaOH(aq) + 2H₂O(l) → Na₂[Zn(OH)₄](aq) + H₂(g)
Here's a breakdown:
* Zinc (Zn) reacts with sodium hydroxide (NaOH) in the presence of water (H₂O).
* The reaction produces sodium tetrahydroxozincate(II) (Na₂[Zn(OH)₄]), a soluble complex ion, and hydrogen gas (H₂) .
Observations:
* You will see bubbles of hydrogen gas evolving from the solution.
* The zinc metal will dissolve, and the solution will become clear.
* The solution will be slightly basic due to the presence of hydroxide ions.
Important Notes:
* This reaction is an example of a redox reaction. Zinc is oxidized (loses electrons) to form Zn²⁺ ions, while hydrogen ions in water are reduced (gain electrons) to form hydrogen gas.
* The reaction is favored in the presence of excess hydroxide ions. This is because the formation of the tetrahydroxozincate(II) complex ion removes zinc ions from the solution, driving the reaction forward.
Let me know if you'd like to know more about the reaction or any of the products formed!
