• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Understanding the Oxidation Number of Nitrogen in Hydrazine (N₂H₄)
    You are correct, the oxidation number of nitrogen (N) in hydrazine (N₂H₄) is -2. Here's how we determine that:

    Understanding Oxidation Numbers

    * Oxidation numbers are a way of keeping track of the electrons in a molecule or ion. They represent the hypothetical charge an atom would have if all the bonds were ionic.

    * Rules for assigning oxidation numbers:

    * The oxidation number of an element in its elemental form is 0.

    * The oxidation number of a monatomic ion is equal to its charge.

    * The oxidation number of oxygen in most compounds is -2 (except in peroxides, where it's -1).

    * The oxidation number of hydrogen in most compounds is +1 (except in metal hydrides, where it's -1).

    * The sum of the oxidation numbers in a neutral molecule is 0.

    * The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

    Applying the rules to hydrazine (N₂H₄):

    1. Hydrogen's oxidation number: In hydrazine, hydrogen is bonded to nitrogen, so its oxidation number is +1.

    2. Let x be the oxidation number of nitrogen: Since there are two nitrogen atoms in hydrazine, the total oxidation number for nitrogen is 2x.

    3. Sum of oxidation numbers: The sum of the oxidation numbers in hydrazine must equal zero: 2x + 4(+1) = 0

    4. Solve for x: 2x + 4 = 0 => 2x = -4 => x = -2

    Therefore, the oxidation number of nitrogen in hydrazine is -2.

    Science Discoveries © www.scienceaq.com