Here's how to calculate the moles of sodium chloride (NaCl) present:

1. Convert mL to L:

* 22.0 mL * (1 L / 1000 mL) = 0.0220 L

2. Use the molarity formula:

* Molarity (M) = moles of solute (mol) / volume of solution (L)

3. Rearrange to solve for moles:

* moles of solute (mol) = Molarity (M) * volume of solution (L)

4. Plug in the values:

* moles of NaCl = 0.500 M * 0.0220 L = 0.0110 moles

Therefore, there are 0.0110 moles of sodium chloride present in 22.0 mL of a 0.500 M solution.