1. Determine the Molecular Formula:
* Propanol has the molecular formula C₃H₇OH.
2. Calculate the Molar Mass:
* Carbon (C): 3 atoms * 12.01 g/mol = 36.03 g/mol
* Hydrogen (H): 8 atoms * 1.01 g/mol = 8.08 g/mol
* Oxygen (O): 1 atom * 16.00 g/mol = 16.00 g/mol
* Total Molar Mass of Propanol: 36.03 + 8.08 + 16.00 = 60.11 g/mol
3. Calculate the Percent Composition for Each Element:
* Carbon (C): (36.03 g/mol / 60.11 g/mol) * 100% = 60.00%
* Hydrogen (H): (8.08 g/mol / 60.11 g/mol) * 100% = 13.44%
* Oxygen (O): (16.00 g/mol / 60.11 g/mol) * 100% = 26.63%
Therefore, the percent composition of propanol is:
* Carbon: 60.00%
* Hydrogen: 13.44%
* Oxygen: 26.63%
