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  • Balancing Ionic Equations: Al + HCl - A Step-by-Step Guide
    Here's how to write the balanced ionic equation for the reaction of aluminum (Al) with hydrochloric acid (HCl):

    1. Write the unbalanced molecular equation:

    2 Al(s) + 6 HCl(aq) → 2 AlCl₃(aq) + 3 H₂(g)

    2. Identify the spectator ions:

    Spectator ions are ions that appear on both sides of the equation and don't participate in the actual reaction. In this case, the chloride ions (Cl⁻) are spectator ions.

    3. Write the complete ionic equation:

    2 Al(s) + 6 H⁺(aq) + 6 Cl⁻(aq) → 2 Al³⁺(aq) + 6 Cl⁻(aq) + 3 H₂(g)

    4. Cancel out the spectator ions:

    2 Al(s) + 6 H⁺(aq) → 2 Al³⁺(aq) + 3 H₂(g)

    5. Simplify the equation:

    Al(s) + 3 H⁺(aq) → Al³⁺(aq) + 3/2 H₂(g)

    This is the balanced ionic equation for the reaction of aluminum with hydrochloric acid.

    Key points:

    * Aluminum (Al) is a solid metal.

    * Hydrochloric acid (HCl) is an aqueous solution.

    * Aluminum chloride (AlCl₃) is an aqueous solution.

    * Hydrogen gas (H₂) is produced as a gas.

    * The coefficients in the balanced equation ensure that the number of atoms of each element is the same on both sides of the equation.

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