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  • Calculating Normality: Determining Na₂CO₃ Mass for a 0.02 N Solution
    Let's break down why 1.06 g of Na₂CO₃ is added to 1 liter of water to prepare a 0.02 N solution.

    Understanding Normality (N)

    * Normality is a concentration unit that measures the number of equivalents of a solute per liter of solution.

    * An equivalent is the amount of a substance that can react with or replace one mole of hydrogen ions (H⁺) or hydroxide ions (OH⁻).

    Na₂CO₃ and Equivalents

    * Sodium carbonate (Na₂CO₃) is a base. When it dissolves in water, it reacts with water to produce carbonate ions (CO₃²⁻), which can accept two hydrogen ions (H⁺).

    * Therefore, one mole of Na₂CO₃ is equivalent to two equivalents (because it can accept two moles of H⁺).

    Calculating the Mass Needed

    1. Molar mass of Na₂CO₃: 105.99 g/mol

    2. Equivalents per mole: 2 equivalents/mol (as explained above)

    3. Desired normality: 0.02 N

    4. Volume of solution: 1 L

    Calculations:

    * Grams of Na₂CO₃ needed: (0.02 N) * (1 L) * (105.99 g/mol) / (2 equivalents/mol) = 1.06 g

    Conclusion

    Adding 1.06 g of Na₂CO₃ to 1 liter of water produces a 0.02 N solution because this mass provides the correct number of equivalents of Na₂CO₃ to achieve the desired normality.

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