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  • Calculating pH and pOH of a Strong Base Solution
    Here's how to calculate the pH and pOH of a 2.34 x 10⁻⁵ M NaOH solution:

    Understanding the Concepts

    * NaOH is a strong base: This means it dissociates completely in water, producing hydroxide ions (OH⁻).

    * pH and pOH:

    * pH measures the acidity of a solution (lower pH = more acidic).

    * pOH measures the basicity of a solution (lower pOH = more basic).

    * Relationship between pH and pOH: pH + pOH = 14

    Calculations

    1. Find the concentration of hydroxide ions [OH⁻]:

    Since NaOH dissociates completely, the concentration of OH⁻ ions is equal to the initial concentration of NaOH:

    [OH⁻] = 2.34 x 10⁻⁵ M

    2. Calculate the pOH:

    pOH = -log[OH⁻]

    pOH = -log(2.34 x 10⁻⁵)

    pOH ≈ 4.63

    3. Calculate the pH:

    pH + pOH = 14

    pH = 14 - pOH

    pH = 14 - 4.63

    pH ≈ 9.37

    Therefore, the pH of the 2.34 x 10⁻⁵ M NaOH solution is approximately 9.37, and the pOH is approximately 4.63.

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