1. Write the Balanced Chemical Equation:

First, we need to know the chemical formula for amyl alcohol (also known as pentanol) and the products of its combustion.

* Amyl alcohol: C₅H₁₁OH

* Combustion products: CO₂ and H₂O

The balanced equation is:

C₅H₁₁OH + 7O₂ → 5CO₂ + 6H₂O

2. Determine the Mole Ratio:

The balanced equation tells us that for every 1 mole of amyl alcohol burned, 5 moles of CO₂ are produced.

3. Calculate Grams of CO₂:

* Molar mass of CO₂: 12.01 g/mol (C) + 2 * 16.00 g/mol (O) = 44.01 g/mol

* Grams of CO₂ produced: 1.0 mol amyl alcohol * (5 mol CO₂ / 1 mol amyl alcohol) * (44.01 g CO₂ / 1 mol CO₂) = 220.05 g CO₂

Therefore, 220.05 grams of CO₂ are produced from the burning of 1.0 mol of amyl alcohol.