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  • Calculating Osmolarity of 0.4 M Ammonium Phosphate ((NH₄)₃PO₄) - A Detailed Explanation
    Here's how to calculate the osmolarity of 0.4 M Ammonium Phosphate ((NH₄)₃PO₄):

    Understanding Osmolarity

    * Osmolarity is a measure of the total concentration of solute particles in a solution. It's expressed in osmoles per liter (Osm/L).

    * One osmole represents 6.022 x 10²³ particles (Avogadro's number) of a solute.

    Calculating Osmolarity

    1. Dissociation: Ammonium phosphate dissociates in solution as follows:

    (NH₄)₃PO₄ → 3 NH₄⁺ + PO₄³⁻

    2. Number of Ions: This means that each mole of (NH₄)₃PO₄ produces 4 moles of ions (3 moles of NH₄⁺ and 1 mole of PO₄³⁻).

    3. Osmolarity Calculation:

    * Molarity (M) = 0.4 M

    * Number of ions per formula unit = 4

    * Osmolarity = Molarity x Number of ions

    * Osmolarity = 0.4 M x 4 = 1.6 Osm/L

    Therefore, the osmolarity of a 0.4 M Ammonium Phosphate solution is 1.6 Osm/L.

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