1/λ = R (1/n₁² - 1/n₂²)
where:
* λ is the wavelength of the emitted light
* R is the Rydberg constant (approximately 1.097 x 10⁷ m⁻¹)
* n₁ is the lower energy level (n=3 in this case)
* n₂ is the higher energy level (n=5 in this case)
Let's plug in the values:
1/λ = (1.097 x 10⁷ m⁻¹) (1/3² - 1/5²)
1/λ = (1.097 x 10⁷ m⁻¹) (1/9 - 1/25)
1/λ = (1.097 x 10⁷ m⁻¹) (16/225)
1/λ ≈ 7.82 x 10⁵ m⁻¹
Now, solve for λ:
λ ≈ 1.28 x 10⁻⁶ m
Therefore, the wavelength of light emitted during this transition is approximately 1.28 x 10⁻⁶ meters, or 1280 nanometers. This falls within the infrared region of the electromagnetic spectrum.