1. Calculate the molar mass of potassium hydroxide (KOH)

* K: 39.10 g/mol

* O: 16.00 g/mol

* H: 1.01 g/mol

* Total molar mass: 39.10 + 16.00 + 1.01 = 56.11 g/mol

2. Calculate the moles of KOH in 8.42 g

* Moles = mass / molar mass

* Moles = 8.42 g / 56.11 g/mol = 0.150 mol

3. Use the molarity to find the volume

* Molarity (M) = moles of solute / volume of solution (L)

* We know the molarity (2.26 M) and the moles (0.150 mol), so we can rearrange the equation to solve for volume:

* Volume (L) = moles / molarity

* Volume (L) = 0.150 mol / 2.26 mol/L = 0.0664 L

4. Convert liters to milliliters

* 1 L = 1000 mL

* Volume (mL) = 0.0664 L * 1000 mL/L = 66.4 mL

Therefore, you would need 66.4 mL of a 2.26 M potassium hydroxide solution to contain 8.42 g of solute.