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  • Bismuth-210 Decay to Lead-206: A Step-by-Step Explanation
    The decay of Bismuth-210 to Lead-206 involves two steps:

    Step 1: Beta decay

    * Bismuth-210 (²¹⁰Bi) decays into Polonium-210 (²¹⁰Po) by emitting a beta particle (electron) and an antineutrino:

    ²¹⁰Bi → ²¹⁰Po + e⁻ + ν̅ₑ

    Step 2: Alpha decay

    * Polonium-210 (²¹⁰Po) then decays into Lead-206 (²⁰⁶Pb) by emitting an alpha particle (helium nucleus):

    ²¹⁰Po → ²⁰⁶Pb + ⁴He

    Overall reaction:

    The overall reaction can be summarized as:

    ²¹⁰Bi → ²⁰⁶Pb + ⁴He + e⁻ + ν̅ₑ

    Note:

    * The half-life of Bismuth-210 is 5.013 days, while Polonium-210 has a half-life of 138.376 days.

    * This decay series is an example of a radioactive decay chain, where one radioactive isotope decays into another, eventually leading to a stable isotope (Lead-206 in this case).

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