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  • Calculating Bromine Required for Complete Reaction with Titanium
    Here's how to solve this problem:

    1. Write the Balanced Chemical Equation:

    The reaction between titanium (Ti) and bromine (Br₂) produces titanium(IV) bromide (TiBr₄):

    Ti + 2 Br₂ → TiBr₄

    2. Calculate the Molar Masses:

    * Ti: 47.87 g/mol

    * Br₂: 159.80 g/mol

    3. Calculate the Moles of Titanium:

    moles of Ti = mass of Ti / molar mass of Ti

    moles of Ti = 22.1 g / 47.87 g/mol

    moles of Ti = 0.462 mol

    4. Use the Mole Ratio from the Balanced Equation:

    The balanced equation shows that 1 mole of Ti reacts with 2 moles of Br₂.

    5. Calculate the Moles of Bromine:

    moles of Br₂ = 0.462 mol Ti * (2 mol Br₂ / 1 mol Ti)

    moles of Br₂ = 0.924 mol

    6. Calculate the Mass of Bromine:

    mass of Br₂ = moles of Br₂ * molar mass of Br₂

    mass of Br₂ = 0.924 mol * 159.80 g/mol

    mass of Br₂ = 147.7 g

    Answer: You would need 147.7 grams of bromine to completely react with 22.1 grams of titanium.

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