1. Calculate moles of chloride ions from each solution:
* NH₄Cl:
- Moles of NH₄Cl = (0.2450 mol/L) * (0.0250 L) = 0.006125 mol
- Since NH₄Cl dissociates into one chloride ion per formula unit, moles of Cl⁻ from NH₄Cl = 0.006125 mol
* FeCl₃:
- Moles of FeCl₃ = (0.1655 mol/L) * (0.0555 L) = 0.009193 mol
- FeCl₃ dissociates into three chloride ions per formula unit, so moles of Cl⁻ from FeCl₃ = 0.009193 mol * 3 = 0.027579 mol
2. Calculate the total moles of chloride ions:
* Total moles of Cl⁻ = 0.006125 mol + 0.027579 mol = 0.033704 mol
3. Calculate the total volume of the final solution:
* Total volume = 25.0 mL + 55.5 mL = 80.5 mL = 0.0805 L
4. Calculate the concentration of chloride ions in the final solution:
* [Cl⁻] = (Total moles of Cl⁻) / (Total volume)
* [Cl⁻] = (0.033704 mol) / (0.0805 L) = 0.419 M
Therefore, the concentration of chloride ions in the final solution is 0.419 M.
