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  • Calculating Entropy Change for Water Vaporization: A Step-by-Step Guide
    Here's how to calculate the entropy change for the vaporization of water:

    Understanding Entropy and Vaporization

    * Entropy (ΔS) is a measure of disorder or randomness in a system. When a substance changes state from liquid to gas, the molecules become more spread out and disordered, leading to an increase in entropy.

    * Vaporization (or boiling) is the process where a liquid changes into a gas.

    Calculations

    1. Find the enthalpy of vaporization (ΔHvap):

    * The enthalpy of vaporization of water at 100°C is approximately 40.7 kJ/mol.

    2. Use the Clausius-Clapeyron equation:

    * The Clausius-Clapeyron equation relates enthalpy of vaporization (ΔHvap) to the change in entropy (ΔSvap) during vaporization:

    ```

    ΔSvap = ΔHvap / T

    ```

    * Where:

    * ΔSvap is the entropy change of vaporization

    * ΔHvap is the enthalpy of vaporization (in J/mol)

    * T is the temperature in Kelvin (K)

    3. Convert temperature to Kelvin:

    * 100°C + 273.15 = 373.15 K

    4. Calculate the entropy change:

    * ΔSvap = (40.7 kJ/mol) / (373.15 K)

    * ΔSvap = 0.109 kJ/(mol·K)

    * Convert to J/(mol·K): ΔSvap = 109 J/(mol·K)

    5. Calculate the entropy change for 1.8 mol of water:

    * ΔS_total = ΔSvap * n

    * ΔS_total = (109 J/(mol·K)) * (1.8 mol)

    * ΔS_total = 196.2 J/K

    Therefore, the entropy change for the vaporization of 1.8 mol of water at 100°C and 1 atm is approximately 196.2 J/K.

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