Here's the chemical equation:
Br₂ (l) + H₂O (l) ⇌ HBr (aq) + HOBr (aq)
Explanation:
* Bromine (Br₂) is a diatomic molecule, meaning it exists as two bromine atoms bonded together. In its liquid form, it has a reddish-brown color.
* Water (H₂O) is a polar molecule, meaning it has a slightly positive and slightly negative end due to the uneven sharing of electrons.
* Bromine acid (HBr) is a strong acid that dissociates completely in water.
* Hypobromous acid (HOBr) is a weak acid, meaning it only partially dissociates in water.
The reaction is reversible:
* The reaction proceeds in both directions, meaning bromine acid and hypobromous acid can react to reform bromine and water.
* The position of the equilibrium (the point where the forward and reverse rates are equal) is shifted by factors like temperature and concentration.
Key points:
* Disproportionation: This reaction is an example of disproportionation, where the same element undergoes both oxidation and reduction. Bromine is oxidized to form HOBr and reduced to form HBr.
* Applications: This reaction is important in various applications, including:
* Water disinfection: HOBr is a powerful disinfectant, used in pools and water treatment systems.
* Organic synthesis: HOBr is a useful reagent in organic chemistry.
Let me know if you'd like to explore the mechanism or applications in more detail!
