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  • Net Ionic Equation: KOH + H2SO4 Reaction Explained
    Here's how to determine the net ionic equation for the reaction of potassium hydroxide (KOH) and sulfuric acid (H₂SO₄):

    1. Write the complete ionic equation:

    * KOH(aq) → K⁺(aq) + OH⁻(aq)

    * H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq)

    * K₂SO₄(aq) → 2K⁺(aq) + SO₄²⁻(aq)

    * H₂O(l) → H₂O(l) (Water remains as a molecule)

    Complete ionic equation:

    2K⁺(aq) + 2OH⁻(aq) + 2H⁺(aq) + SO₄²⁻(aq) → 2H₂O(l) + 2K⁺(aq) + SO₄²⁻(aq)

    2. Identify and cancel spectator ions:

    * Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this case, K⁺(aq) and SO₄²⁻(aq) are spectator ions.

    3. Write the net ionic equation:

    2OH⁻(aq) + 2H⁺(aq) → 2H₂O(l)

    Simplified net ionic equation:

    OH⁻(aq) + H⁺(aq) → H₂O(l)

    Therefore, the net ionic equation for the reaction is OH⁻(aq) + H⁺(aq) → H₂O(l). This equation represents the fundamental reaction between hydroxide ions and hydrogen ions to form water.

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