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  • Calculating Atoms in Barium Phosphate: A Step-by-Step Guide
    Here's how to calculate the number of atoms in 0.0350 mol of barium phosphate (Ba₃(PO₄)₂):

    1. Determine the number of atoms per formula unit:

    * Barium phosphate (Ba₃(PO₄)₂) has:

    * 3 barium (Ba) atoms

    * 2 phosphorus (P) atoms

    * 8 oxygen (O) atoms

    * Total: 3 + 2 + 8 = 13 atoms per formula unit

    2. Calculate the number of formula units:

    * Avogadro's number tells us that there are 6.022 x 10²³ formula units in one mole of any substance.

    * Therefore, 0.0350 mol of barium phosphate contains:

    * 0.0350 mol * (6.022 x 10²³ formula units/mol) = 2.108 x 10²² formula units

    3. Calculate the total number of atoms:

    * Multiply the number of formula units by the number of atoms per formula unit:

    * (2.108 x 10²² formula units) * (13 atoms/formula unit) = 2.74 x 10²³ atoms

    Therefore, there are approximately 2.74 x 10²³ atoms present in 0.0350 mol of barium phosphate.

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