Here's how to balance the chemical equation for the reaction of sulfurous acid (H₂SO₃) and aluminum hydroxide (Al(OH)₃) to produce aluminum sulfite (Al₂(SO₃)₃) and water (H₂O):

Unbalanced Equation:

H₂SO₃ + Al(OH)₃ → Al₂(SO₃)₃ + H₂O

Balancing the Equation:

1. Balance Aluminum (Al): There are 2 Al atoms on the product side and 1 on the reactant side. Add a coefficient of 2 in front of Al(OH)₃:

H₂SO₃ + 2 Al(OH)₃ → Al₂(SO₃)₃ + H₂O

2. Balance Sulfur (S): There are 3 S atoms on the product side and 1 on the reactant side. Add a coefficient of 3 in front of H₂SO₃:

3 H₂SO₃ + 2 Al(OH)₃ → Al₂(SO₃)₃ + H₂O

3. Balance Oxygen (O): There are 12 O atoms on the product side and 12 on the reactant side.

4. Balance Hydrogen (H): There are 12 H atoms on the reactant side and 2 on the product side. Add a coefficient of 6 in front of H₂O:

3 H₂SO₃ + 2 Al(OH)₃ → Al₂(SO₃)₃ + 6 H₂O

Balanced Equation:

3 H₂SO₃ + 2 Al(OH)₃ → Al₂(SO₃)₃ + 6 H₂O

Coefficients:

* H₂SO₃: 3

* Al(OH)₃: 2

* Al₂(SO₃)₃: 1

* H₂O: 6