1. Determine the molar mass of CuCl₂:
* Copper (Cu): 63.55 g/mol
* Chlorine (Cl): 35.45 g/mol (x2 for two chlorine atoms)
* Total molar mass of CuCl₂ = 63.55 g/mol + (35.45 g/mol x 2) = 134.45 g/mol
2. Calculate the mass percentage of each element:
* Copper (Cu): (63.55 g/mol / 134.45 g/mol) x 100% = 47.26%
* Chlorine (Cl): (70.90 g/mol / 134.45 g/mol) x 100% = 52.74%
Therefore, the percent composition of copper(II) chloride is:
* Copper (Cu): 47.26%
* Chlorine (Cl): 52.74%
