1. Calculate the moles of NaOH:
* Molarity (M) = moles of solute / liters of solution
* We know the molarity (0.010 M) and the volume (2.5 L). We can rearrange the equation to solve for moles:
* moles of NaOH = Molarity * volume
* moles of NaOH = 0.010 mol/L * 2.5 L = 0.025 moles
2. Calculate the mass of NaOH:
* moles = mass / molar mass
* The molar mass of NaOH is 40 g/mol (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H)
* We can rearrange the equation to solve for mass:
* mass = moles * molar mass
* mass of NaOH = 0.025 mol * 40 g/mol = 1.0 g
Therefore, 2.5 L of a 0.010 M NaOH solution contains 1.0 g of NaOH.
