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  • Oxidation State of Oxygen in HOF: A Comprehensive Guide
    Here's how to determine the oxidation state of oxygen in HOF (hypofluorous acid):

    Understanding Oxidation States

    * Oxidation state is a number assigned to an atom in a molecule or ion that represents its hypothetical charge if all bonds were 100% ionic.

    * Rules:

    * The oxidation state of a free element is always 0.

    * The sum of oxidation states in a neutral molecule is 0.

    * The sum of oxidation states in a polyatomic ion equals the charge of the ion.

    * Fluorine (F) has an oxidation state of -1 in its compounds (except in F₂).

    * Hydrogen (H) has an oxidation state of +1 in its compounds (except in metal hydrides, where it is -1).

    Applying the Rules to HOF

    1. Fluorine's oxidation state: Fluorine always has an oxidation state of -1, so F is -1 in HOF.

    2. Hydrogen's oxidation state: Hydrogen is bonded to a more electronegative element (oxygen), so its oxidation state is +1.

    3. Oxygen's oxidation state (let's call it "x"): Since the overall charge of HOF is 0, we can set up the equation:

    (+1) + (x) + (-1) = 0

    4. Solving for x:

    x = 0

    Therefore, the oxidation state of oxygen in HOF is 0.

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