Here's how to write the molecular, full ionic, and net ionic equations for the reaction between copper(II) nitrate and lithium hydroxide:

1. Molecular Equation

* Reactants: Copper(II) nitrate (Cu(NO₃)₂) and lithium hydroxide (LiOH)

* Products: Copper(II) hydroxide (Cu(OH)₂) - a blue-green precipitate - and lithium nitrate (LiNO₃)

Equation:

Cu(NO₃)₂(aq) + 2LiOH(aq) → Cu(OH)₂(s) + 2LiNO₃(aq)

2. Full Ionic Equation

* Break down all soluble ionic compounds into their ions.

* Remember that solids (s) remain as a single unit.

Equation:

Cu²⁺(aq) + 2NO₃⁻(aq) + 2Li⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s) + 2Li⁺(aq) + 2NO₃⁻(aq)

3. Net Ionic Equation

* Cancel out spectator ions (ions that appear on both sides of the equation and don't participate in the reaction).

Equation:

Cu²⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s)

Summary

* Molecular Equation: Cu(NO₃)₂(aq) + 2LiOH(aq) → Cu(OH)₂(s) + 2LiNO₃(aq)

* Full Ionic Equation: Cu²⁺(aq) + 2NO₃⁻(aq) + 2Li⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s) + 2Li⁺(aq) + 2NO₃⁻(aq)

* Net Ionic Equation: Cu²⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s)