Here's how to determine the net ionic equation for the reaction between copper(II) sulfate (CuSO₄) and sodium phosphate (Na₃PO₄):

1. Write the balanced molecular equation:

3CuSO₄(aq) + 2Na₃PO₄(aq) → Cu₃(PO₄)₂(s) + 3Na₂SO₄(aq)

2. Write the complete ionic equation:

This involves breaking down all soluble ionic compounds into their respective ions:

3Cu²⁺(aq) + 3SO₄²⁻(aq) + 6Na⁺(aq) + 2PO₄³⁻(aq) → Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 3SO₄²⁻(aq)

3. Identify spectator ions:

Spectator ions are those that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Na⁺ and SO₄²⁻.

4. Write the net ionic equation:

Remove the spectator ions from the complete ionic equation:

3Cu²⁺(aq) + 2PO₄³⁻(aq) → Cu₃(PO₄)₂(s)

Therefore, the net ionic equation for the reaction of copper(II) sulfate and sodium phosphate is:

3Cu²⁺(aq) + 2PO₄³⁻(aq) → Cu₃(PO₄)₂(s)