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  • Ionic Bond Formation: Calculating Barium and Chlorine Atom Ratio
    Here's how to determine the number of chlorine atoms needed to form an ionic bond with barium:

    * Barium (Ba) has two valence electrons. It wants to lose these two electrons to achieve a stable octet (8 electrons) in its outer shell.

    * Chlorine (Cl) has seven valence electrons. It wants to gain one electron to achieve a stable octet.

    To balance the charges:

    * Barium will lose two electrons, becoming a Ba²⁺ ion.

    * Two chlorine atoms will each gain one electron, becoming two Cl⁻ ions.

    Therefore, you need two chlorine atoms to form an ionic bond with one barium atom. This results in the compound barium chloride (BaCl₂).

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