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  • Lithium and Bromine Reaction: Oxidation and Reduction Explained
    Here's how to determine what's oxidized and reduced in the reaction between lithium metal and bromine:

    Understanding Oxidation and Reduction

    * Oxidation: Loss of electrons. The oxidation number of an element increases.

    * Reduction: Gain of electrons. The oxidation number of an element decreases.

    The Reaction

    The reaction between lithium (Li) and bromine (Br₂) produces lithium bromide (LiBr):

    2 Li(s) + Br₂(l) → 2 LiBr(s)

    Analyzing Oxidation States

    * Lithium (Li):

    * Starts as elemental lithium, with an oxidation state of 0.

    * In LiBr, it becomes Li⁺, with an oxidation state of +1. This means lithium has *lost* an electron, so it has been oxidized.

    * Bromine (Br₂):

    * Starts as elemental bromine, with an oxidation state of 0.

    * In LiBr, it becomes Br⁻, with an oxidation state of -1. This means bromine has *gained* an electron, so it has been reduced.

    Summary

    * Lithium is oxidized. It loses an electron and its oxidation state increases from 0 to +1.

    * Bromine is reduced. It gains an electron and its oxidation state decreases from 0 to -1.

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