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  • Nitrogen Atom Calculation in Copper(II) Nitrate (10.2g)
    Here's how to calculate the number of nitrogen atoms in 10.2 g of copper(II) nitrate:

    1. Determine the formula of copper(II) nitrate:

    * Copper(II) has a +2 charge (Cu²⁺).

    * Nitrate has a -1 charge (NO₃⁻).

    * To balance the charges, we need two nitrate ions for every copper(II) ion. The formula is Cu(NO₃)₂.

    2. Calculate the molar mass of copper(II) nitrate:

    * Cu: 63.55 g/mol

    * N: 14.01 g/mol (x2 because there are two nitrogen atoms)

    * O: 16.00 g/mol (x6 because there are six oxygen atoms)

    * Molar mass = 63.55 + (14.01 x 2) + (16.00 x 6) = 187.57 g/mol

    3. Calculate the number of moles of copper(II) nitrate:

    * Moles = mass / molar mass

    * Moles = 10.2 g / 187.57 g/mol = 0.0544 mol

    4. Calculate the number of moles of nitrogen atoms:

    * Since there are two nitrogen atoms per formula unit of copper(II) nitrate, there are twice as many moles of nitrogen atoms as moles of copper(II) nitrate.

    * Moles of nitrogen = 0.0544 mol Cu(NO₃)₂ * 2 mol N / 1 mol Cu(NO₃)₂ = 0.1088 mol N

    5. Calculate the number of nitrogen atoms:

    * Use Avogadro's number (6.022 x 10²³ atoms/mol) to convert moles to atoms.

    * Number of nitrogen atoms = 0.1088 mol N * 6.022 x 10²³ atoms/mol = 6.55 x 10²² atoms

    Therefore, there are approximately 6.55 x 10²² nitrogen atoms in 10.2 g of copper(II) nitrate.

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