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  • Sodium's Electron Loss: Understanding Electropositivity and Ion Formation
    Yes, sodium (Na) readily gives up its outermost electron to other atoms. Here's why:

    * Electron Configuration: Sodium has one electron in its outermost shell (valence shell). This single electron is loosely bound and relatively easy to remove.

    * Electropositivity: Sodium is highly electropositive, meaning it has a strong tendency to lose electrons and become positively charged.

    * Octet Rule: By losing one electron, sodium achieves a stable octet configuration in its outermost shell, which is a more energetically favorable state.

    How Sodium Forms Ions:

    When sodium reacts with other atoms, it loses its outermost electron to form a positively charged ion, Na⁺. This process is called ionization.

    Examples:

    * Reaction with Chlorine: Sodium reacts with chlorine to form sodium chloride (NaCl). Sodium loses its electron to chlorine, forming Na⁺ and Cl⁻ ions, which then attract each other due to their opposite charges.

    * Reaction with Water: Sodium reacts vigorously with water, releasing hydrogen gas and forming sodium hydroxide (NaOH). The sodium atom loses its electron to form Na⁺ ions.

    In summary, sodium's tendency to lose its outermost electron makes it a highly reactive element that readily forms ionic bonds with other elements.

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