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  • Lead(II) Nitrate and Potassium Iodide Reaction: A Double Displacement Explained
    The chemical reaction between lead(II) nitrate (Pb(NO₃)₂) and potassium iodide (KI) is a double displacement reaction.

    Here's why:

    * Double displacement reactions involve the exchange of ions between two reactants. In this case, the lead(II) ions (Pb²⁺) from lead(II) nitrate combine with the iodide ions (I⁻) from potassium iodide to form lead(II) iodide (PbI₂), which is a yellow precipitate.

    * The remaining ions, potassium (K⁺) and nitrate (NO₃⁻), also combine to form potassium nitrate (KNO₃), which remains dissolved in solution.

    The balanced chemical equation for this reaction is:

    Pb(NO₃)₂ (aq) + 2 KI (aq) → PbI₂ (s) + 2 KNO₃ (aq)

    Here's a breakdown:

    * Reactants: Lead(II) nitrate (Pb(NO₃)₂) and potassium iodide (KI) are both aqueous solutions (aq).

    * Products: Lead(II) iodide (PbI₂) is a yellow solid precipitate (s), while potassium nitrate (KNO₃) remains in solution (aq).

    This reaction is also considered a precipitation reaction because the formation of the insoluble lead(II) iodide causes it to precipitate out of the solution.

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