1. Write the complete molecular equation:
HClO₄(aq) + NaClO(aq) → NaClO₄(aq) + HClO(aq)
2. Identify the soluble ionic compounds and write them as ions:
* HClO₄(aq) → H⁺(aq) + ClO₄⁻(aq)
* NaClO(aq) → Na⁺(aq) + ClO⁻(aq)
* NaClO₄(aq) → Na⁺(aq) + ClO₄⁻(aq)
* HClO(aq) remains as a weak acid (it doesn't dissociate significantly)
3. Write the complete ionic equation:
H⁺(aq) + ClO₄⁻(aq) + Na⁺(aq) + ClO⁻(aq) → Na⁺(aq) + ClO₄⁻(aq) + HClO(aq)
4. Cancel out spectator ions:
Na⁺ and ClO₄⁻ appear on both sides of the equation, so they are spectator ions and can be canceled out.
5. Write the net ionic equation:
H⁺(aq) + ClO⁻(aq) → HClO(aq)
This is the balanced net ionic equation for the reaction.