1. Calculate the Molar Mass of Lithium Sulfate (Li₂SO₄)
* Li: 6.941 g/mol (x2) = 13.882 g/mol
* S: 32.06 g/mol
* O: 16.00 g/mol (x4) = 64.00 g/mol
Total molar mass = 13.882 + 32.06 + 64.00 = 110.942 g/mol
2. Convert Grams of Lithium Sulfate to Moles
* Moles = (Mass in grams) / (Molar mass)
* Moles = 734 g / 110.942 g/mol
* Moles ≈ 6.61 mol
3. Convert Milliliters of Solution to Liters
* Liters = Milliliters / 1000
* Liters = 2500 mL / 1000
* Liters = 2.5 L
4. Calculate Molarity
* Molarity (M) = (Moles of solute) / (Liters of solution)
* Molarity = 6.61 mol / 2.5 L
* Molarity ≈ 2.64 M
Therefore, the molarity of the lithium sulfate solution is approximately 2.64 M.
