CuSO₄(aq) + 2 NaC₂H₃O₂(aq) → Cu(C₂H₃O₂)₂(s) + Na₂SO₄(aq)
Here's a breakdown of the reaction:
* Reactants:
* Copper(II) sulfate (CuSO₄) is a blue crystalline solid that is soluble in water.
* Sodium acetate (NaC₂H₃O₂) is a white crystalline solid that is soluble in water.
* Products:
* Copper(II) acetate (Cu(C₂H₃O₂)₂) is a blue-green solid that is sparingly soluble in water. It precipitates out of solution.
* Sodium sulfate (Na₂SO₄) is a white crystalline solid that is soluble in water.
Explanation:
The reaction involves a double displacement reaction, where the cations and anions of the reactants switch places. This leads to the formation of copper(II) acetate, which is less soluble than the other compounds. The copper(II) acetate precipitates out of solution, leaving sodium sulfate dissolved in water.
Key points:
* The reaction is balanced by ensuring that the number of atoms of each element is the same on both sides of the equation.
* The state symbols (aq) and (s) indicate whether the substances are aqueous (dissolved in water) or solid, respectively.
* The reaction is reversible, meaning that under certain conditions, copper(II) acetate can react with sodium sulfate to reform copper(II) sulfate and sodium acetate.
