When cupric sulfate (CuSO₄) and Fe metal react, they undergo a single displacement reaction. This means that the more reactive metal, iron (Fe), will displace the less reactive metal, copper (Cu), from its compound.

Here's what happens:

* Iron (Fe) reacts with cupric sulfate (CuSO₄):

Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)

* Products:

* Iron(II) sulfate (FeSO₄): This is formed when iron displaces copper in the solution.

* Copper (Cu): Copper is deposited as a solid, which you can observe as a reddish-brown coating on the iron.

In summary, the reaction of cupric sulfate and Fe metal leaves you with iron(II) sulfate in solution and solid copper.