1. Convert grams to moles:

* Nitrogen (N2):

- Molar mass of N2 = 28.02 g/mol

- Moles of N2 = (2.00 g) / (28.02 g/mol) = 0.0714 mol

* Hydrogen (H2):

- Molar mass of H2 = 2.02 g/mol

- Moles of H2 = (3.00 g) / (2.02 g/mol) = 1.49 mol

2. Determine the limiting reactant:

* The balanced equation shows that 1 mole of N2 reacts with 3 moles of H2.

* We have 0.0714 mol of N2, which would require 3 * 0.0714 = 0.214 mol of H2.

* Since we have more than enough H2 (1.49 mol), N2 is the limiting reactant.

3. Calculate moles of NH3 produced:

* The balanced equation shows that 1 mole of N2 produces 2 moles of NH3.

* Moles of NH3 produced = 0.0714 mol N2 * (2 mol NH3 / 1 mol N2) = 0.143 mol NH3

Therefore, 0.143 moles of NH3 can be produced.