1. Write the balanced chemical equation:
The combustion of propanal (C₃H₆O) produces carbon dioxide (CO₂) and water (H₂O):
C₃H₆O + 4O₂ → 3CO₂ + 3H₂O
2. Determine the mole ratio of water to propanal:
From the balanced equation, we see that 1 mol of propanal (C₃H₆O) produces 3 mol of water (H₂O).
3. Convert moles of water to grams:
* The molar mass of water (H₂O) is 18.015 g/mol.
* Using the mole ratio and the molar mass of water:
3 mol H₂O × 18.015 g/mol = 54.045 g H₂O
Therefore, 54.045 grams of water are formed when 1 mol of propanal burns.
