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  • Ionic Equation: NaOH(aq) + HCl(aq) Reaction - Complete Breakdown
    Here's how to write the complete ionic equation for the reaction of NaOH(aq) and HCl(aq):

    1. Identify the strong electrolytes:

    * NaOH(aq): Sodium hydroxide is a strong base, meaning it completely ionizes in solution.

    * HCl(aq): Hydrochloric acid is a strong acid, also completely ionizing in solution.

    * NaCl(aq): Sodium chloride is a soluble salt, so it fully dissociates in solution.

    2. Write the complete ionic equation:

    Break down the strong electrolytes into their respective ions:

    * NaOH(aq) → Na+(aq) + OH-(aq)

    * HCl(aq) → H+(aq) + Cl-(aq)

    * NaCl(aq) → Na+(aq) + Cl-(aq)

    3. Combine the ions and include water:

    Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → H2O(l) + Na+(aq) + Cl-(aq)

    4. Cancel out spectator ions:

    Spectator ions are those that appear on both sides of the equation and don't participate in the reaction. In this case, Na+ and Cl- are spectator ions.

    Final Complete Ionic Equation:

    OH-(aq) + H+(aq) → H2O(l)

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