Here's a breakdown of the reaction:
Reaction:
Br₂(l) + 2NaI(aq) → I₂(aq) + 2NaBr(aq)
Explanation:
* Bromine (Br₂) is a stronger oxidizing agent than iodine (I₂). This means that bromine is more likely to gain electrons and get reduced.
* Iodide ions (I⁻) are oxidized by bromine. They lose electrons and become iodine molecules (I₂).
* Bromine gets reduced by gaining electrons from iodide ions and becomes bromide ions (Br⁻).
* Sodium ions (Na⁺) remain unchanged as spectator ions.
Observations:
* The solution turns brown/red. This is due to the formation of iodine, which is brown/red in color.
* The reaction is exothermic, meaning it releases heat.
Note: This reaction is a classic example of a halogen displacement reaction, where a more reactive halogen displaces a less reactive halogen from its salt solution.
