* Beryllium is more reactive than tin. This means beryllium would displace tin from its compound, not the other way around.

* Iodide is more reactive than nitrate. This means iodide would remain bound to beryllium, not switch to tin.

Here's a more accurate representation of the reaction:

BeI₂(aq) + Sn(NO₃)₂(aq) → No reaction

Explanation:

* Beryllium iodide (BeI₂) and tin(II) nitrate (Sn(NO₃)₂) are both soluble in water, forming aqueous solutions.

* However, because beryllium is more reactive than tin, there is no displacement reaction.

* The reactants will simply remain in solution.

A possible reaction involving beryllium iodide and a tin compound:

BeI₂(aq) + Sn(s) → Be(s) + SnI₂(aq)

This reaction would occur because solid tin is more reactive than solid beryllium. The beryllium would be displaced, forming solid beryllium and aqueous tin(II) iodide.