1. Formula Units
* Avogadro's Number: One mole of any substance contains 6.022 x 10²³ particles (atoms, molecules, or formula units).
* Calculation:
(6.75 moles AlCl₃) * (6.022 x 10²³ formula units/mole) = 4.06 x 10²⁴ formula units of AlCl₃
2. Ions
* Dissociation: AlCl₃ dissociates into one aluminum ion (Al³⁺) and three chloride ions (Cl⁻) in solution:
AlCl₃ → Al³⁺ + 3Cl⁻
* Calculation:
* Aluminum Ions (Al³⁺):
(4.06 x 10²⁴ formula units AlCl₃) * (1 Al³⁺ ion/formula unit) = 4.06 x 10²⁴ Al³⁺ ions
* Chloride Ions (Cl⁻):
(4.06 x 10²⁴ formula units AlCl₃) * (3 Cl⁻ ions/formula unit) = 1.22 x 10²⁵ Cl⁻ ions
Summary:
* 6.75 moles of AlCl₃ contains 4.06 x 10²⁴ formula units of AlCl₃.
* This amount also contains 4.06 x 10²⁴ Al³⁺ ions and 1.22 x 10²⁵ Cl⁻ ions.
