1. Write the Balanced Chemical Equation:

The reaction between lithium (Li) and nitrogen gas (N₂) produces lithium nitride (Li₃N):

6 Li + N₂ → 2 Li₃N

2. Calculate Moles of Nitrogen Gas:

* At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L.

* Convert the volume of nitrogen gas to liters: 60.00 mL = 0.06000 L

* Use the molar volume of a gas to find moles:

(0.06000 L N₂) * (1 mol N₂ / 22.4 L N₂) = 0.002679 mol N₂

3. Determine the Mole Ratio:

* From the balanced equation, 1 mole of N₂ reacts with 6 moles of Li.

4. Calculate Moles of Lithium:

* Use the mole ratio to find the moles of Li needed:

(0.002679 mol N₂) * (6 mol Li / 1 mol N₂) = 0.01607 mol Li

5. Calculate Mass of Lithium:

* Use the molar mass of Li (6.941 g/mol) to convert moles to grams:

(0.01607 mol Li) * (6.941 g Li / 1 mol Li) = 0.1117 g Li

Therefore, 0.1117 grams of lithium are required to react completely with 60.00 mL of nitrogen gas at STP.