The chemical equation for the reaction of chlorine with sodium iodide is:

Cl₂(g) + 2NaI(aq) → 2NaCl(aq) + I₂(s)

Here's what happens in this reaction:

* Chlorine (Cl₂) gas is a more reactive halogen than iodine.

* Sodium iodide (NaI) is a soluble ionic compound.

* The chlorine displaces the iodine in the sodium iodide, forming sodium chloride (NaCl), which is also soluble.

* The displaced iodine (I₂) forms a solid precipitate.

This reaction is a classic example of a single displacement reaction, where a more reactive element displaces a less reactive element from a compound. You can observe this reaction by adding chlorine gas to a solution of sodium iodide. The solution will turn brown due to the formation of iodine.