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  • Fluorine Atoms in CF4: A Step-by-Step Calculation
    Here's how to solve this problem:

    1. Calculate the molar mass of CF4

    * Carbon (C) has a molar mass of 12.01 g/mol

    * Fluorine (F) has a molar mass of 19.00 g/mol

    * Molar mass of CF4 = 12.01 + (4 * 19.00) = 88.01 g/mol

    2. Calculate the moles of CF4

    * Moles = Mass / Molar mass

    * Moles of CF4 = 65 g / 88.01 g/mol = 0.738 mol

    3. Calculate the moles of fluorine atoms

    * There are 4 fluorine atoms per molecule of CF4.

    * Moles of fluorine atoms = 0.738 mol CF4 * (4 mol F atoms / 1 mol CF4) = 2.95 mol F atoms

    4. Calculate the number of fluorine atoms

    * Avogadro's number: 6.022 x 10^23 atoms/mol

    * Number of fluorine atoms = 2.95 mol * 6.022 x 10^23 atoms/mol = 1.78 x 10^24 atoms

    Therefore, there are approximately 1.78 x 10^24 fluorine atoms in 65g of CF4.

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