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  • Calculating Moles of Sodium Ions in Sodium Phosphate Solution
    Here's how to solve this problem:

    1. Understand the Formula:

    * Na₃PO₄ represents sodium phosphate. It contains 3 sodium ions (Na⁺) for every one phosphate ion (PO₄³⁻).

    2. Calculate Moles of Na₃PO₄:

    * Molarity (M) is moles of solute per liter of solution.

    * Moles of Na₃PO₄ = Molarity × Volume

    * Moles of Na₃PO₄ = 0.300 M × 2.50 L = 0.750 moles

    3. Calculate Moles of Na⁺:

    * Since there are 3 sodium ions per formula unit of Na₃PO₄:

    * Moles of Na⁺ = 3 × Moles of Na₃PO₄

    * Moles of Na⁺ = 3 × 0.750 moles = 2.25 moles

    Answer: There are 2.25 moles of sodium ions present in 2.50 L of 0.300 M Na₃PO₄ solution.

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